From a bag containing 8 green and 5 red balls
WebCorrect option is A) Let number of blue balls in the bag =x Total no of balls in bag =5+x [No. of redball =5] Probability of drawing a blue ball = Total no of ballNo. of blue ball P(B)= 5+xx Probability of drawing a Red ball = Total no of ballNo. of red ball P(R)= 5+x5 Given, P(B)=2P(R) 5+xx =2(5+x5) x=10 Hence, no. of blue balls in the bag =10. WebProbability of getting at least 1 green ball = 1 – P (getting no green ball) Calculation: A bag contains 5 blue balls, 7 green balls and 8 red balls. ⇒ Probability of getting no green ball = 13/20 Probability of getting at least 1 green ball …
From a bag containing 8 green and 5 red balls
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WebA bag contains 6 red balls, 8 white balls, 5 green balls and 2 black balls. One ball is drawn at random from the bag. Then total number of balls in bag =6+8+5+2+1=22. Total number of out come =22. (i)The event is getting a White ball=number of white ball in bag=8. Then probability= 228 = 114. WebThere are 12 balls in a bag. 3 of them are red, 4 of them are green, and 5 of them are blue. We randomly take out 3 balls from the bag at the same time. What is the probability that all three balls are of the same colour? My answer: ( 3 / …
WebA jar contains 4 black marbles and 3 red marbles. Two marbles are drawn without replacement. a) Draw the tree diagram for the experiment. b) Find probabilities for P(BB), P(BR), P(RB), P(WW), P(at least one Red), P(exactly one red) Two marbles are drawn without replacement from a jar containing 4 black and 6 white marbles. WebCalculation: A bag contains 5 blue balls, 7 green balls and 8 red balls. ⇒ Probability of getting no green ball = 13/20. Probability of getting at least 1 green ball = 1 – P (getting no green ball out of two balls drawn) ⇒ Probability of getting at least 1 green ball = 1 – (13/20 × 12/19) = 56/95.
WebA box contains 4 white balls, 6 red ball, 7 black balls and 3 blue balls. One ball is drawn at random from the bag. Find the probability that the ball drawn is : (i) neither white nor black (ii) red or white, and (iii) either white or red or black or blue WebA bag contains 6 red balls and 8 green balls. A ball is drawn at random . What is the probability that the ball is green. Easy. View solution > A bag contains 5 red and 3 blue balls. If 3 balls are drawn at random without replacement then the probability that two of the three balls were red, the first ball being red, is.
WebSolution. GIVEN: A bag contains5 red, 8 green and 7 white balls. TO FIND: Probability of getting a white ball or a green ball. Total number of balls=5+8+7=20. Total number of green or white balls=8+7=15. We know that PROBABILITY = Number of favourable event Total number of event.
WebDec 12, 2016 · A bag contains 6 red balls and 7 green balls. You plan to select 5 balls at random. What is the probability of selecting (without replacement) 5 green balls? eval army siteWebA bag contains 6 red balls and 8 green balls. If two balls are drawn together what is the probability that both are red? Alternatively, you can consider the two draws separately (the arithmetic is identical): 6/14 chance to draw your first ball as red (now there remain 5 red balls and 8 green balls so 13 total) evalang ressourcesWebA bag contains 15 red, 8 blue and several green marbles. A marble is selected at random. A marble is selected at random. The probability of drawing a blue marble is 1 5 . first baptist of gainesvilleWebSep 14, 2024 · Best answer Given that: Number of red balls = 8 Number of white balls = 5 ∴ Total balls, n = 13 It is given that 3 balls are drawn at random ⇒ r = 3 ∴ n (S) = nCr = 13C3 (a) All the three balls are white We know that, Total white balls are = 5 (b) All the three balls are red We know that, Total red balls are = 8 eva larue hd wallpaperWebAug 14, 2015 · A bag labeled A contains 4 red balls and 7 green balls. Another bag B contains 6 red and 5 green balls. A ball is transferred from bag A to bag B, after which a ball is drawn from B. Find the probability that it is a red ball? eva larsson wahlbergWebMar 22, 2024 · Get live Maths 1-on-1 Classs - Class 6 to 12 Book 30 minute class for ₹ 499 ₹ 299 Transcript Ex 7.4, 8 A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected. Hence No. of ways in which 2 black & 3 red balls can be selected = 10 × 20 = 200 ways Next: Ex 7.4, 9 → Ask a doubt first baptist of fort lauderdaleWebMar 22, 2024 · Total number of balls in the bag = 5 + 3 = 8 Number of red balls = 3 Probability of getting a red ball = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑟𝑒𝑑 𝑏𝑎𝑙𝑙𝑠)/ (𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑏𝑎𝑙𝑙𝑠) = 3/8 Ex15.1, 8 A bag contains 3 red balls and 5 black balls. A ball is drawn at random from ... eva larue worth